Write a Number Sentence Question: Sam put 18 pencils in 3 equal groups. How many pencils are in each group?
Strategy:
1) UNDERSTAND:
What do you need to know?
You need to know that there are 18 pencils and they are divided into 3 equal groups
2) PLAN:
How can you solve the problem?
You can write a number sentence to solve the problem. Write a division sentence to divide the pencils in 3 equal groups.
3) SOLVE:
18 รท 3 = 6
There are 6 pencils in each group.
ALGEBRA: Bob is currently twice as old as Steve. Twenty years ago Bob was 6 times as old as Steve. What are their current ages?
For the algebraic approach we know that if something is twice as old, big, fast, etc as something else it is 2x more than x. So in this problem Bob is 2x as old as x Steve is.
Twenty years ago would be :
2x - 20 for Bob
and
x - 20 for Steve
but, 20 years ago Bob was 6 times older so
2x - 20 = 6(x - 20)
2x - 20 = 6x - 120
4x = 100
x = 100/4
x = 25
So x or Bob is 25 and Steve is twice or 2(25): 50 years old. If Steve's current age was 20 then 20 years ago he would be zero, so he has to be at least 21 years old. This would make Bob 42 and Steve 21. 20 years ago they would be 22 and 1, which is 22 times as old and not 6 times. Were not that far off though. So go up by increments. Try Steve at 22 and Bob 44-- 20 years ago would be 2 and 24 which is 12 times-- at 23 and 46 we can see than 20 years ago they would be 3 and 26 which is over 8 times were close-- and at 24 and 48 20 years ago would make 4 and 28 which is 7 times and really close.. at 25 and 50 20 years ago we would have 5 and 30 which IS 6 times older and what were looking for. So, Steve is 25 and Bob is 50...
Question: Sam put 18 pencils in 3 equal groups. How many pencils are in each group?
Strategy:
1) UNDERSTAND:
What do you need to know?
You need to know that there are 18 pencils and they are divided into 3 equal groups
2) PLAN:
How can you solve the problem?
You can write a number sentence to solve the problem. Write a division sentence to divide the pencils in 3 equal groups.
3) SOLVE:
18 รท 3 = 6
There are 6 pencils in each group.
ALGEBRA:
Bob is currently twice as old as Steve. Twenty years ago Bob was 6 times as old as Steve. What are their current ages?
For the algebraic approach we know that if something is twice as old, big, fast, etc as something else it is 2x more than x. So in this problem Bob is 2x as old as x Steve is.
Twenty years ago would be :
2x - 20 for Bob
and
x - 20 for Steve
but, 20 years ago Bob was 6 times older so
2x - 20 = 6(x - 20)
2x - 20 = 6x - 120
4x = 100
x = 100/4
x = 25
So x or Bob is 25 and Steve is twice or 2(25): 50 years old.
If Steve's current age was 20 then 20 years ago he would be zero, so he has to be at least 21 years old. This would make Bob 42 and Steve 21. 20 years ago they would be 22 and 1, which is 22 times as old and not 6 times. Were not that far off though. So go up by increments. Try Steve at 22 and Bob 44-- 20 years ago would be 2 and 24 which is 12 times-- at 23 and 46 we can see than 20 years ago they would be 3 and 26 which is over 8 times were close-- and at 24 and 48 20 years ago would make 4 and 28 which is 7 times and really close.. at 25 and 50 20 years ago we would have 5 and 30 which IS 6 times older and what were looking for. So, Steve is 25 and Bob is 50...